(10/x-2)-(5/x)=-3/x

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Solution for (10/x-2)-(5/x)=-3/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x-(5/x)-2 = -3/x // + -3/x

10/x-(5/x)-(-3/x)-2 = 0

10/x-5*x^-1+3*x^-1-2 = 0

8*x^-1 = 2 // : 8

x^-1 = 1/4

-1 < 0

1/(x^1) = 1/4 // * x^1

1 = 1/4*x^1 // : 1/4

4 = x^1

x = 4

x = 4

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