(10/x-2)=(15/6+x)

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Solution for (10/x-2)=(15/6+x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x-2 = x+15/6 // - x+15/6

10/x-x-(15/6)-2 = 0

10/x-x-5/2-2 = 0

10*x^-1-1*x^1-9/2*x^0 = 0

(10*x^0-1*x^2-9/2*x^1)/(x^1) = 0 // * x^2

x^1*(10*x^0-1*x^2-9/2*x^1) = 0

x^1

(-9/2)*x-x^2+10 = 0

(-9/2)*x-x^2+10 = 0

DELTA = (-9/2)^2-(-1*4*10)

DELTA = 241/4

DELTA > 0

x = ((241/4)^(1/2)-(-9/2))/(-1*2) or x = (-(-9/2)-(241/4)^(1/2))/(-1*2)

x = ((241/4)^(1/2)+9/2)/(-2) or x = (9/2-(241/4)^(1/2))/(-2)

x in { ((241/4)^(1/2)+9/2)/(-2), (9/2-(241/4)^(1/2))/(-2)} 

x in { ((241/4)^(1/2)+9/2)/(-2), (9/2-(241/4)^(1/2))/(-2) }

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