(100-2x)(80-2x)=8000

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Solution for (100-2x)(80-2x)=8000 equation:



(100-2x)(80-2x)=8000
We move all terms to the left:
(100-2x)(80-2x)-(8000)=0
We add all the numbers together, and all the variables
(-2x+100)(-2x+80)-8000=0
We multiply parentheses ..
(+4x^2-160x-200x+8000)-8000=0
We get rid of parentheses
4x^2-160x-200x+8000-8000=0
We add all the numbers together, and all the variables
4x^2-360x=0
a = 4; b = -360; c = 0;
Δ = b2-4ac
Δ = -3602-4·4·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-360}{2*4}=\frac{0}{8} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+360}{2*4}=\frac{720}{8} =90 $

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