(103-2x)+(4x-58)=180

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Solution for (103-2x)+(4x-58)=180 equation: 



(103-2x)+(4x-58)=180

We move all terms to the left:

(103-2x)+(4x-58)-(180)=0

We add all the numbers together, and all the variables

(-2x+103)+(4x-58)-180=0

We get rid of parentheses

-2x+4x+103-58-180=0

We add all the numbers together, and all the variables

2x-135=0

We move all terms containing x to the left, all other terms to the right

2x=135

x=135/2

x=67+1/2

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