(10b-9)-3(3b+1)=-6

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Solution for (10b-9)-3(3b+1)=-6 equation: 



(10b-9)-3(3b+1)=-6

We move all terms to the left:

(10b-9)-3(3b+1)-(-6)=0

We add all the numbers together, and all the variables

(10b-9)-3(3b+1)+6=0

We multiply parentheses

(10b-9)-9b-3+6=0

We get rid of parentheses

10b-9b-9-3+6=0

We add all the numbers together, and all the variables

b-6=0

We move all terms containing b to the left, all other terms to the right

b=6

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