(10p+3)(2p-1)=0

Solution for (10p+3)(2p-1)=0 equation:

(10p+3)(2p-1)=0

We multiply parentheses ..

(+20p^2-10p+6p-3)=0

We get rid of parentheses

20p^2-10p+6p-3=0

We add all the numbers together, and all the variables

20p^2-4p-3=0

a = 20; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·20·(-3)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*20}=\frac{-12}{40}
=-3/10
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*20}=\frac{20}{40}
=1/2
$