(10r-20)=(2r+12)

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Solution for (10r-20)=(2r+12) equation: 



(10r-20)=(2r+12)

We move all terms to the left:

(10r-20)-((2r+12))=0

We get rid of parentheses

10r-((2r+12))-20=0



We calculate terms in parentheses: -((2r+12)), so:

(2r+12)

We get rid of parentheses

2r+12

Back to the equation:

-(2r+12)



We get rid of parentheses

10r-2r-12-20=0

We add all the numbers together, and all the variables

8r-32=0

We move all terms containing r to the left, all other terms to the right

8r=32

r=32/8

r=4

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