(10v+5)11v-44)=0

Solution for (10v+5)11v-44)=0 equation:

(10v+5)11v-44)=0

We add all the numbers together, and all the variables

(10v+5)11v=0

We multiply parentheses

110v^2+55v=0

a = 110; b = 55; c = 0;
Δ = b2-4ac
Δ = 552-4·110·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-55}{2*110}=\frac{-110}{220}
=-1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+55}{2*110}=\frac{0}{220}
=0
$