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(10w+120)(45w+25)=0
We multiply parentheses ..
(+450w^2+250w+5400w+3000)=0
We get rid of parentheses
450w^2+250w+5400w+3000=0
We add all the numbers together, and all the variables
450w^2+5650w+3000=0
a = 450; b = 5650; c = +3000;
Δ = b2-4ac
Δ = 56502-4·450·3000
Δ = 26522500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{26522500}=5150$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5650)-5150}{2*450}=\frac{-10800}{900} =-12 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5650)+5150}{2*450}=\frac{-500}{900} =-5/9 $
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