(10x(1+2x)=)

Solution for (10x(1+2x)=) equation:

(10x(1+2x)=)

We move all terms to the left:

(10x(1+2x)-())=0

We add all the numbers together, and all the variables

(10x(2x+1)-())=0


We calculate terms in parentheses: +(10x(2x+1)-()), so:

10x(2x+1)-()

We add all the numbers together, and all the variables

10x(2x+1)

We multiply parentheses

20x^2+10x

Back to the equation:

+(20x^2+10x)


We get rid of parentheses

20x^2+10x=0

a = 20; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·20·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*20}=\frac{-20}{40}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*20}=\frac{0}{40}
=0
$