(10x)(7/4)(2)=70

Solution for (10x)(7/4)(2)=70 equation:

(10x)(7/4)(2)=70

We move all terms to the left:

(10x)(7/4)(2)-(70)=0

We add all the numbers together, and all the variables

10x(+7/4)2-70=0

We multiply parentheses

140x^2-70=0

a = 140; b = 0; c = -70;
Δ = b2-4ac
Δ = 02-4·140·(-70)
Δ = 39200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39200}=\sqrt{19600*2}=\sqrt{19600}*\sqrt{2}=140\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140\sqrt{2}}{2*140}=\frac{0-140\sqrt{2}}{280}
=-\frac{140\sqrt{2}}{280}
=-\frac{\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140\sqrt{2}}{2*140}=\frac{0+140\sqrt{2}}{280}
=\frac{140\sqrt{2}}{280}
=\frac{\sqrt{2}}{2}
$