(10x)+(4x-10)+(49)=180

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Solution for (10x)+(4x-10)+(49)=180 equation:



(10x)+(4x-10)+(49)=180
We move all terms to the left:
(10x)+(4x-10)+(49)-(180)=0
We add all the numbers together, and all the variables
10x+(4x-10)-131=0
We get rid of parentheses
10x+4x-10-131=0
We add all the numbers together, and all the variables
14x-141=0
We move all terms containing x to the left, all other terms to the right
14x=141
x=141/14
x=10+1/14

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