(10x)+(4x-10)+(49)=180

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Solution for (10x)+(4x-10)+(49)=180 equation: 



(10x)+(4x-10)+(49)=180

We move all terms to the left:

(10x)+(4x-10)+(49)-(180)=0

We add all the numbers together, and all the variables

10x+(4x-10)-131=0

We get rid of parentheses

10x+4x-10-131=0

We add all the numbers together, and all the variables

14x-141=0

We move all terms containing x to the left, all other terms to the right

14x=141

x=141/14

x=10+1/14

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