(10x)+(x-2)+(20x-4)=180

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Solution for (10x)+(x-2)+(20x-4)=180 equation: 



(10x)+(x-2)+(20x-4)=180

We move all terms to the left:

(10x)+(x-2)+(20x-4)-(180)=0

We get rid of parentheses

10x+x+20x-2-4-180=0

We add all the numbers together, and all the variables

31x-186=0

We move all terms containing x to the left, all other terms to the right

31x=186

x=186/31

x=6

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