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(10x+1)/(6x-4)=5/3
We move all terms to the left:
(10x+1)/(6x-4)-(5/3)=0
Domain of the equation: (6x-4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
6x!=4
x!=4/6
x!=2/3
x∈R
(10x+1)/(6x-4)-(+5/3)=0
We get rid of parentheses
(10x+1)/(6x-4)-5/3=0
We calculate fractions
(30x+3)/(18x-12)+(-30x+20)/(18x-12)=0
We multiply all the terms by the denominator
(30x+3)+(-30x+20)=0
We get rid of parentheses
30x-30x+3+20=0
We add all the numbers together, and all the variables
23!=0
There is no solution for this equation
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