(10x+12)(5x)=180

Solution for (10x+12)(5x)=180 equation:

(10x+12)(5x)=180

We move all terms to the left:

(10x+12)(5x)-(180)=0

We multiply parentheses

50x^2+60x-180=0

a = 50; b = 60; c = -180;
Δ = b2-4ac
Δ = 602-4·50·(-180)
Δ = 39600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39600}=\sqrt{3600*11}=\sqrt{3600}*\sqrt{11}=60\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{11}}{2*50}=\frac{-60-60\sqrt{11}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{11}}{2*50}=\frac{-60+60\sqrt{11}}{100}
$