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(10x+15)-3=2(2x+6+3x)
We move all terms to the left:
(10x+15)-3-(2(2x+6+3x))=0
We add all the numbers together, and all the variables
(10x+15)-(2(5x+6))-3=0
We get rid of parentheses
10x-(2(5x+6))+15-3=0
We calculate terms in parentheses: -(2(5x+6)), so:We add all the numbers together, and all the variables
2(5x+6)
We multiply parentheses
10x+12
Back to the equation:
-(10x+12)
10x-(10x+12)+12=0
We get rid of parentheses
10x-10x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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