(10x+16)+(2x+3)+(3x+11)=180

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Solution for (10x+16)+(2x+3)+(3x+11)=180 equation: 



(10x+16)+(2x+3)+(3x+11)=180

We move all terms to the left:

(10x+16)+(2x+3)+(3x+11)-(180)=0

We get rid of parentheses

10x+2x+3x+16+3+11-180=0

We add all the numbers together, and all the variables

15x-150=0

We move all terms containing x to the left, all other terms to the right

15x=150

x=150/15

x=10

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