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(10x+2)(x-7)=0
We multiply parentheses ..
(+10x^2-70x+2x-14)=0
We get rid of parentheses
10x^2-70x+2x-14=0
We add all the numbers together, and all the variables
10x^2-68x-14=0
a = 10; b = -68; c = -14;
Δ = b2-4ac
Δ = -682-4·10·(-14)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-72}{2*10}=\frac{-4}{20} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+72}{2*10}=\frac{140}{20} =7 $
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