(10x+20)=(72-3x)

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Solution for (10x+20)=(72-3x) equation: 



(10x+20)=(72-3x)

We move all terms to the left:

(10x+20)-((72-3x))=0

We add all the numbers together, and all the variables

(10x+20)-((-3x+72))=0

We get rid of parentheses

10x-((-3x+72))+20=0



We calculate terms in parentheses: -((-3x+72)), so:

(-3x+72)

We get rid of parentheses

-3x+72

Back to the equation:

-(-3x+72)



We get rid of parentheses

10x+3x-72+20=0

We add all the numbers together, and all the variables

13x-52=0

We move all terms containing x to the left, all other terms to the right

13x=52

x=52/13

x=4

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