(10x+20)=(8x-2)

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Solution for (10x+20)=(8x-2) equation: 



(10x+20)=(8x-2)

We move all terms to the left:

(10x+20)-((8x-2))=0

We get rid of parentheses

10x-((8x-2))+20=0



We calculate terms in parentheses: -((8x-2)), so:

(8x-2)

We get rid of parentheses

8x-2

Back to the equation:

-(8x-2)



We get rid of parentheses

10x-8x+2+20=0

We add all the numbers together, and all the variables

2x+22=0

We move all terms containing x to the left, all other terms to the right

2x=-22

x=-22/2

x=-11

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