(10x+4)=(6x+32)

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Solution for (10x+4)=(6x+32) equation: 



(10x+4)=(6x+32)

We move all terms to the left:

(10x+4)-((6x+32))=0

We get rid of parentheses

10x-((6x+32))+4=0



We calculate terms in parentheses: -((6x+32)), so:

(6x+32)

We get rid of parentheses

6x+32

Back to the equation:

-(6x+32)



We get rid of parentheses

10x-6x-32+4=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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