(10x+4/2)+7=5(x+1)

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Solution for (10x+4/2)+7=5(x+1) equation: 



(10x+4/2)+7=5(x+1)

We move all terms to the left:

(10x+4/2)+7-(5(x+1))=0

We add all the numbers together, and all the variables

(10x+2)-(5(x+1))+7=0

We get rid of parentheses

10x-(5(x+1))+2+7=0



We calculate terms in parentheses: -(5(x+1)), so:

5(x+1)

We multiply parentheses

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

10x-(5x+5)+9=0

We get rid of parentheses

10x-5x-5+9=0

We add all the numbers together, and all the variables

5x+4=0

We move all terms containing x to the left, all other terms to the right

5x=-4

x=-4/5

x=-4/5

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