(10x+5)(x)=50

Solution for (10x+5)(x)=50 equation:

(10x+5)(x)=50

We move all terms to the left:

(10x+5)(x)-(50)=0

We multiply parentheses

10x^2+5x-50=0

a = 10; b = 5; c = -50;
Δ = b2-4ac
Δ = 52-4·10·(-50)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-45}{2*10}=\frac{-50}{20}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+45}{2*10}=\frac{40}{20}
=2
$