(10x+5)+(4x-6)=31

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Solution for (10x+5)+(4x-6)=31 equation: 



(10x+5)+(4x-6)=31

We move all terms to the left:

(10x+5)+(4x-6)-(31)=0

We get rid of parentheses

10x+4x+5-6-31=0

We add all the numbers together, and all the variables

14x-32=0

We move all terms containing x to the left, all other terms to the right

14x=32

x=32/14

x=2+2/7

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