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(10x+5)x=6
We move all terms to the left:
(10x+5)x-(6)=0
We multiply parentheses
10x^2+5x-6=0
a = 10; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·10·(-6)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{265}}{2*10}=\frac{-5-\sqrt{265}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{265}}{2*10}=\frac{-5+\sqrt{265}}{20} $
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