(10x+50)/(x+4)=x+5

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Solution for (10x+50)/(x+4)=x+5 equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(10*x+50)/(x+4) = x+5 // - x+5

(10*x+50)/(x+4)-x-5 = 0

(10*x+50)/(x+4)+(-x*(x+4))/(x+4)+(-5*(x+4))/(x+4) = 0

10*x-x*(x+4)-5*(x+4)+50 = 0

6*x-x^2-5*x-20+50 = 0

x-x^2+30 = 0

x-x^2+30 = 0

x-x^2+30 = 0

DELTA = 1^2-(-1*4*30)

DELTA = 121

DELTA > 0

x = (121^(1/2)-1)/(-1*2) or x = (-121^(1/2)-1)/(-1*2)

x = -5 or x = 6

(x+5)*(x-6) = 0

((x+5)*(x-6))/(x+4) = 0

((x+5)*(x-6))/(x+4) = 0 // * x+4

(x+5)*(x-6) = 0

( x+5 )

x+5 = 0 // - 5

x = -5

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -5, 6 }

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