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(10x+7)(2x+7)=0
We multiply parentheses ..
(+20x^2+70x+14x+49)=0
We get rid of parentheses
20x^2+70x+14x+49=0
We add all the numbers together, and all the variables
20x^2+84x+49=0
a = 20; b = 84; c = +49;
Δ = b2-4ac
Δ = 842-4·20·49
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-56}{2*20}=\frac{-140}{40} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+56}{2*20}=\frac{-28}{40} =-7/10 $
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