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(10x+8)2x+136=180
We move all terms to the left:
(10x+8)2x+136-(180)=0
We add all the numbers together, and all the variables
(10x+8)2x-44=0
We multiply parentheses
20x^2+16x-44=0
a = 20; b = 16; c = -44;
Δ = b2-4ac
Δ = 162-4·20·(-44)
Δ = 3776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3776}=\sqrt{64*59}=\sqrt{64}*\sqrt{59}=8\sqrt{59}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{59}}{2*20}=\frac{-16-8\sqrt{59}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{59}}{2*20}=\frac{-16+8\sqrt{59}}{40} $
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