(10x+9)x-(5x-1)(2x+3)=8

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Solution for (10x+9)x-(5x-1)(2x+3)=8 equation: 



(10x+9)x-(5x-1)(2x+3)=8

We move all terms to the left:

(10x+9)x-(5x-1)(2x+3)-(8)=0

We multiply parentheses

10x^2+9x-(5x-1)(2x+3)-8=0

We multiply parentheses ..

10x^2-(+10x^2+15x-2x-3)+9x-8=0

We get rid of parentheses

10x^2-10x^2-15x+2x+9x+3-8=0

We add all the numbers together, and all the variables

-4x-5=0

We move all terms containing x to the left, all other terms to the right

-4x=5

x=5/-4

x=-1+1/4

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