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(10x-1)(3+4x)=0
We add all the numbers together, and all the variables
(10x-1)(4x+3)=0
We multiply parentheses ..
(+40x^2+30x-4x-3)=0
We get rid of parentheses
40x^2+30x-4x-3=0
We add all the numbers together, and all the variables
40x^2+26x-3=0
a = 40; b = 26; c = -3;
Δ = b2-4ac
Δ = 262-4·40·(-3)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-34}{2*40}=\frac{-60}{80} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+34}{2*40}=\frac{8}{80} =1/10 $
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