(10x-1)=(3x+4)+(3x+19)

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Solution for (10x-1)=(3x+4)+(3x+19) equation: 



(10x-1)=(3x+4)+(3x+19)

We move all terms to the left:

(10x-1)-((3x+4)+(3x+19))=0

We get rid of parentheses

10x-((3x+4)+(3x+19))-1=0



We calculate terms in parentheses: -((3x+4)+(3x+19)), so:

(3x+4)+(3x+19)

We get rid of parentheses

3x+3x+4+19

We add all the numbers together, and all the variables

6x+23

Back to the equation:

-(6x+23)



We get rid of parentheses

10x-6x-23-1=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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