(10x-12)=1/2(11x-5)(4x+26)

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Solution for (10x-12)=1/2(11x-5)(4x+26) equation: 



(10x-12)=1/2(11x-5)(4x+26)

We move all terms to the left:

(10x-12)-(1/2(11x-5)(4x+26))=0



Domain of the equation: 2(11x-5)(4x+26))!=0

x∈R



We get rid of parentheses

10x-(1/2(11x-5)(4x+26))-12=0

We multiply parentheses ..

-(1/2(+44x^2+286x-20x-130))+10x-12=0

We multiply all the terms by the denominator


-(1+10x*2(+44x^2+286x-20x-130))-12*2(+44x^2+286x-20x-130))=0



We calculate terms in parentheses: -(1+10x*2(+44x^2+286x-20x-130)), so:

1+10x*2(+44x^2+286x-20x-130)

determiningTheFunctionDomain
10x*2(+44x^2+286x-20x-130)+1

Wy multiply elements

20x^2(++1

We use the square of the difference formula

20x^2(+1

Back to the equation:

-(20x^2(+1)



We add all the numbers together, and all the variables

-(20x^21-12*2(+44x^2+286x-20x-130))=0



We calculate terms in parentheses: -(20x^21-12*2(+44x^2+286x-20x-130)), so:

20x^21-12*2(+44x^2+286x-20x-130)

We do not support expression: x^21

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