(10x-14)+(3x+11)+(3x+15)=180

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Solution for (10x-14)+(3x+11)+(3x+15)=180 equation: 



(10x-14)+(3x+11)+(3x+15)=180

We move all terms to the left:

(10x-14)+(3x+11)+(3x+15)-(180)=0

We get rid of parentheses

10x+3x+3x-14+11+15-180=0

We add all the numbers together, and all the variables

16x-168=0

We move all terms containing x to the left, all other terms to the right

16x=168

x=168/16

x=10+1/2

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