(10x-15)+(4x-10)+(3x+5)=270

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Solution for (10x-15)+(4x-10)+(3x+5)=270 equation: 



(10x-15)+(4x-10)+(3x+5)=270

We move all terms to the left:

(10x-15)+(4x-10)+(3x+5)-(270)=0

We get rid of parentheses

10x+4x+3x-15-10+5-270=0

We add all the numbers together, and all the variables

17x-290=0

We move all terms containing x to the left, all other terms to the right

17x=290

x=290/17

x=17+1/17

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