(10x-15)+(4x-10)+(3x+5)=270

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Solution for (10x-15)+(4x-10)+(3x+5)=270 equation:



(10x-15)+(4x-10)+(3x+5)=270
We move all terms to the left:
(10x-15)+(4x-10)+(3x+5)-(270)=0
We get rid of parentheses
10x+4x+3x-15-10+5-270=0
We add all the numbers together, and all the variables
17x-290=0
We move all terms containing x to the left, all other terms to the right
17x=290
x=290/17
x=17+1/17

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