(10x-19)=(3x+2)=(5x-3)

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Solution for (10x-19)=(3x+2)=(5x-3) equation: 



(10x-19)=(3x+2)=(5x-3)

We move all terms to the left:

(10x-19)-((3x+2))=0

We get rid of parentheses

10x-((3x+2))-19=0



We calculate terms in parentheses: -((3x+2)), so:

(3x+2)

We get rid of parentheses

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

10x-3x-2-19=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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