(10x-2)=(4x-28)

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Solution for (10x-2)=(4x-28) equation: 



(10x-2)=(4x-28)

We move all terms to the left:

(10x-2)-((4x-28))=0

We get rid of parentheses

10x-((4x-28))-2=0



We calculate terms in parentheses: -((4x-28)), so:

(4x-28)

We get rid of parentheses

4x-28

Back to the equation:

-(4x-28)



We get rid of parentheses

10x-4x+28-2=0

We add all the numbers together, and all the variables

6x+26=0

We move all terms containing x to the left, all other terms to the right

6x=-26

x=-26/6

x=-4+1/3

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