(10x-2)=128

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Solution for (10x-2)=128 equation: 



(10x-2)=128

We move all terms to the left:

(10x-2)-(128)=0

We get rid of parentheses

10x-2-128=0

We add all the numbers together, and all the variables

10x-130=0

We move all terms containing x to the left, all other terms to the right

10x=130

x=130/10

x=13

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