(10x-20)+(6x+)=180

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Solution for (10x-20)+(6x+)=180 equation: 



(10x-20)+(6x+)=180

We move all terms to the left:

(10x-20)+(6x+)-(180)=0

We add all the numbers together, and all the variables

(10x-20)+(+6x)-180=0

We get rid of parentheses

10x+6x-20-180=0

We add all the numbers together, and all the variables

16x-200=0

We move all terms containing x to the left, all other terms to the right

16x=200

x=200/16

x=12+1/2

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