(10x-20)=(3x+36)

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Solution for (10x-20)=(3x+36) equation: 



(10x-20)=(3x+36)

We move all terms to the left:

(10x-20)-((3x+36))=0

We get rid of parentheses

10x-((3x+36))-20=0



We calculate terms in parentheses: -((3x+36)), so:

(3x+36)

We get rid of parentheses

3x+36

Back to the equation:

-(3x+36)



We get rid of parentheses

10x-3x-36-20=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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