(10x-20)=(6x/8)

Solution for (10x-20)=(6x/8) equation:

(10x-20)=(6x/8)

We move all terms to the left:

(10x-20)-((6x/8))=0

We add all the numbers together, and all the variables

(10x-20)-((+6x/8))=0

We get rid of parentheses

10x-((+6x/8))-20=0

We multiply all the terms by the denominator


10x*8))-((+6x-20*8))=0

We add all the numbers together, and all the variables

10x*8))-((6x-160))=0

We add all the numbers together, and all the variables

10x*8))-((6x=0

Wy multiply elements

80x^2=0

a = 80; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·80·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{160}=0$