(10x-27)=(2x+29)

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Solution for (10x-27)=(2x+29) equation:



(10x-27)=(2x+29)
We move all terms to the left:
(10x-27)-((2x+29))=0
We get rid of parentheses
10x-((2x+29))-27=0
We calculate terms in parentheses: -((2x+29)), so:
(2x+29)
We get rid of parentheses
2x+29
Back to the equation:
-(2x+29)
We get rid of parentheses
10x-2x-29-27=0
We add all the numbers together, and all the variables
8x-56=0
We move all terms containing x to the left, all other terms to the right
8x=56
x=56/8
x=7

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