(10x-3)(3x+1)=0

Solution for (10x-3)(3x+1)=0 equation:

(10x-3)(3x+1)=0

We multiply parentheses ..

(+30x^2+10x-9x-3)=0

We get rid of parentheses

30x^2+10x-9x-3=0

We add all the numbers together, and all the variables

30x^2+x-3=0

a = 30; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·30·(-3)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*30}=\frac{-20}{60}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*30}=\frac{18}{60}
=3/10
$