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(10x-3)(6x+7)=180
We move all terms to the left:
(10x-3)(6x+7)-(180)=0
We multiply parentheses ..
(+60x^2+70x-18x-21)-180=0
We get rid of parentheses
60x^2+70x-18x-21-180=0
We add all the numbers together, and all the variables
60x^2+52x-201=0
a = 60; b = 52; c = -201;
Δ = b2-4ac
Δ = 522-4·60·(-201)
Δ = 50944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{50944}=\sqrt{256*199}=\sqrt{256}*\sqrt{199}=16\sqrt{199}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-16\sqrt{199}}{2*60}=\frac{-52-16\sqrt{199}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+16\sqrt{199}}{2*60}=\frac{-52+16\sqrt{199}}{120} $
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