(10x-3)+(5x+2)+(7x-11)+(13x-31)+(8x-19)=108

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Solution for (10x-3)+(5x+2)+(7x-11)+(13x-31)+(8x-19)=108 equation: 



(10x-3)+(5x+2)+(7x-11)+(13x-31)+(8x-19)=108

We move all terms to the left:

(10x-3)+(5x+2)+(7x-11)+(13x-31)+(8x-19)-(108)=0

We get rid of parentheses

10x+5x+7x+13x+8x-3+2-11-31-19-108=0

We add all the numbers together, and all the variables

43x-170=0

We move all terms containing x to the left, all other terms to the right

43x=170

x=170/43

x=3+41/43

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