(10x-32)+(9x-12)=127

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Solution for (10x-32)+(9x-12)=127 equation:



(10x-32)+(9x-12)=127
We move all terms to the left:
(10x-32)+(9x-12)-(127)=0
We get rid of parentheses
10x+9x-32-12-127=0
We add all the numbers together, and all the variables
19x-171=0
We move all terms containing x to the left, all other terms to the right
19x=171
x=171/19
x=9

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