(10x-37)=(6x+11)

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Solution for (10x-37)=(6x+11) equation: 



(10x-37)=(6x+11)

We move all terms to the left:

(10x-37)-((6x+11))=0

We get rid of parentheses

10x-((6x+11))-37=0



We calculate terms in parentheses: -((6x+11)), so:

(6x+11)

We get rid of parentheses

6x+11

Back to the equation:

-(6x+11)



We get rid of parentheses

10x-6x-11-37=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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