(10x-3=4x+45)

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Solution for \(10x-3=4x+45\) equation: 



(10x-3=4x+45)

We move all terms to the left:

(10x-3-(4x+45))=0



We calculate terms in parentheses: +(10x-3-(4x+45)), so:

10x-3-(4x+45)

determiningTheFunctionDomain
10x-(4x+45)-3

We get rid of parentheses

10x-4x-45-3

We add all the numbers together, and all the variables

6x-48

Back to the equation:

+(6x-48)



We get rid of parentheses

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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