(10x-4)+6(x+2)=180

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Solution for (10x-4)+6(x+2)=180 equation: 



(10x-4)+6(x+2)=180

We move all terms to the left:

(10x-4)+6(x+2)-(180)=0

We multiply parentheses

(10x-4)+6x+12-180=0

We get rid of parentheses

10x+6x-4+12-180=0

We add all the numbers together, and all the variables

16x-172=0

We move all terms containing x to the left, all other terms to the right

16x=172

x=172/16

x=10+3/4

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