(10x-4)/2)+7=5(x+1)

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Solution for (10x-4)/2)+7=5(x+1) equation: 



(10x-4)/2)+7=5(x+1)

We move all terms to the left:

(10x-4)/2)+7-(5(x+1))=0



Domain of the equation: 2)+7-(5(x+1))!=0

x∈R



We multiply all the terms by the denominator


(10x-4)=0

We get rid of parentheses

10x-4=0

We move all terms containing x to the left, all other terms to the right

10x=4

x=4/10

x=2/5

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