(10x-40)-2=(5x-15)+3

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Solution for (10x-40)-2=(5x-15)+3 equation: 



(10x-40)-2=(5x-15)+3

We move all terms to the left:

(10x-40)-2-((5x-15)+3)=0

We get rid of parentheses

10x-((5x-15)+3)-40-2=0



We calculate terms in parentheses: -((5x-15)+3), so:

(5x-15)+3

We get rid of parentheses

5x-15+3

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We add all the numbers together, and all the variables

10x-(5x-12)-42=0

We get rid of parentheses

10x-5x+12-42=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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